SOLUTION: Find the magnitude and direction ( in degrees) of the vector. v= <(-sqrt(2))/2,(-sqrt(2))/2 >

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Question 1042851: Find the magnitude and direction ( in degrees) of the vector. v= <(-sqrt(2))/2,(-sqrt(2))/2 >
Answer by ikleyn(52863) About Me  (Show Source):
You can put this solution on YOUR website!
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Find the magnitude and direction ( in degrees) of the vector. v= <(-sqrt(2))/2,(-sqrt(2))/2 >
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The magnitude is %28-sqrt%282%29%2F2%29%5E2+%2B+%28-sqrt%282%29%2F2%29%5E2 = 1.

The direction is . . . south-west . . .