SOLUTION: The distance between two stations is 340 km. Two trains start simultaneously from these stations on parallel tracks to cross each other. The speed of one of them is greater than th
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Question 1042699: The distance between two stations is 340 km. Two trains start simultaneously from these stations on parallel tracks to cross each other. The speed of one of them is greater than that of the other by 5 km/hr. If the distance between the two train after 2 HOURS of their start is 30 km , find the speed of each train . Answer by ikleyn(52800) (Show Source):
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The distance between two stations is 340 km.
Two trains start simultaneously from these stations on parallel tracks towards each other.
The speed of one of them is greater than that of the other by 5 km/hr. If the distance between the two train
after 2 HOURS of their start is 30 km , find the speed of each train .
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Let u be the speed of the lower train, in .
Then the speed of the faster train is (u+5) .
During 2 hours one train covered 2u kilometers, while the other train covered 2*(u+5) km.
Together they covered 2u + 2*(u+5) kilometers.
This distance is nothing else as 340-30 = 310 km.
So, you have an equation
2u + 2*(u+5) = 310.
Now simplify and solve it for u.
2u + 2u + 10 = 310,
4u = 310-10 ---> 4u = 300 ---> u = = 75.
Thus the slower train has the speed of 75 .
Then the faster train moves at the speed of 75 + 5 = 80 .
Answer. 75 and 80 .
