SOLUTION: ou have quarters and dimes that total $2.80. Your friend says it is possible that the number of quarters is 8 more than the number of dimes. Is your friend correct? Explain. Let d

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: ou have quarters and dimes that total $2.80. Your friend says it is possible that the number of quarters is 8 more than the number of dimes. Is your friend correct? Explain. Let d       Log On

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Question 1042638: ou have quarters and dimes that total $2.80. Your friend says it is possible that the number of quarters is 8 more than the number of dimes. Is your friend correct? Explain. Let d represent the number of dimes. what is the equation
Answer by solver91311(24713) About Me  (Show Source):
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No. Not possible. Since the total amount of money ends in a 0, it is not possible to have an odd number of quarters. So you have an even number of quarters. If you had 12 quarters, you would have $3.00, which is too much, so the most quarters you could have is 10 quarters, making $2.50, and then you would have 3 dimes to make the additional $0.30 necessary to make the $2.80. 10 is only 7 more than 3, so this combination does not provide a solution where you have 8 more quarters than dimes. If you have 8 quarters making $2.00, you would have 8 dimes also, not a solution. If you have 6 or fewer quarters, it is impossible to have 8 more quarters than dimes.

John

My calculator said it, I believe it, that settles it