SOLUTION: A and B are two independent events. The probability that both occur simultaneously is 1/6 and the
probability that neither occurs is 1/3, then P(A) + P(B) = *?
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-> SOLUTION: A and B are two independent events. The probability that both occur simultaneously is 1/6 and the
probability that neither occurs is 1/3, then P(A) + P(B) = *?
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Question 1042548: A and B are two independent events. The probability that both occur simultaneously is 1/6 and the
probability that neither occurs is 1/3, then P(A) + P(B) = *? Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! P(A∩B) = 1/6 and 1 - P(A∪B) = 1/3, as given.
==> 1 - P(A∪B) = 1 - (P(A) + P(B) - P(A∩B)) = 1/3.
==> 1 + P(A∩B) - 1/3 = P(A) + P(B)
==> 1 + 1/6 -1/3 = P(A) + P(B)
==> P(A) + P(B) = 5/6.
