SOLUTION: Reference question 1042438:
I have found the problem with answers:
A: s / 3 + 4m
B: ms / 3 + 4m
C: s(1 + m) / 3 + 4m
D: s(1 + 2m) / 3 + 4m
I am unsure how to solve. Th
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-> SOLUTION: Reference question 1042438:
I have found the problem with answers:
A: s / 3 + 4m
B: ms / 3 + 4m
C: s(1 + m) / 3 + 4m
D: s(1 + 2m) / 3 + 4m
I am unsure how to solve. Th
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Question 1042532: Reference question 1042438:
I have found the problem with answers:
A: s / 3 + 4m
B: ms / 3 + 4m
C: s(1 + m) / 3 + 4m
D: s(1 + 2m) / 3 + 4m
I am unsure how to solve. Thanks again. Found 2 solutions by josgarithmetic, MathTherapy:Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! A, B, C, and D invest $s. B invests m times as much as A, C as much as A and B combined, and D as much as C and B combined.
Determine amount each invests.
A invests x amount of money.
B invests mx;
C invests mx+x;
D invests (mx)+(mx+x)=2mx+x.
The sum of their investments is stated as s dollars.
Solve this for x but it will be IN TERMS OF s.
Substitute x into the individual investment amounts already listed and simplify.
You can put this solution on YOUR website!
Reference question 1042438:
I have found the problem with answers:
A: s / 3 + 4m
B: ms / 3 + 4m
C: s(1 + m) / 3 + 4m
D: s(1 + 2m) / 3 + 4m
I am unsure how to solve. Thanks again.
Let amount A invests be A
Then amount B invests = mA
Amount C invests = A + mA
Amount D invests = mA + A + mA, or 2mA + A
We then get: A + mA + A + mA + 2mA + A = s
3A + 4mA = s
A(3 + 4m) = s
A, or amount A invests =
Amount B invests: =======>
Amount C invests: ======> ======>
Amount D invests: =======> =======> ======>
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