SOLUTION: Solve sinθ − 2sinθ cosθ = 0 for 0°≤θ≤360°
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Question 1042504
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Solve sinθ − 2sinθ cosθ = 0 for 0°≤θ≤360°
Answer by
Alan3354(69443)
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sin - 2sin*cos = 0
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sin*(1-2cos) = 0
sin = 0
theta = 0, 180 degs
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1-2cos = 0
cos = 1/2
theta = 60, 300 degs