SOLUTION: Jessica drove to her cabin on the lake and back. it took one hour longer to go there than it did to come back. the average speed on the trip there was 50 km/h. the average speed on

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Jessica drove to her cabin on the lake and back. it took one hour longer to go there than it did to come back. the average speed on the trip there was 50 km/h. the average speed on      Log On

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Question 1042461: Jessica drove to her cabin on the lake and back. it took one hour longer to go there than it did to come back. the average speed on the trip there was 50 km/h. the average speed on the way back was 75 km/h. how many hours did the trip there take?
Answer by Alan3354(69443) About Me  (Show Source):
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Jessica drove to her cabin on the lake and back. it took one hour longer to go there than it did to come back. the average speed on the trip there was 50 km/h. the average speed on the way back was 75 km/h. how many hours did the trip there take?
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The distance is the same.
d = r*t
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d = 50*t = 75*(t-1)
Can you solve for t?