Question 1042289: A coin has 33 quarters and nickels. The number of nickels is 5 greater than three times the number of quarters.
a) Define your two variables for the problem.
b) Using your variables from part (a), write two equations to make up your system.
c) Solve the system algebraically (i.e use substitution or elimination).
d) How many quarters are there? How many nickels are there?
Answer by mathslover(157)   (Show Source):
You can put this solution on YOUR website! a)Let the number of nickels = x and the number of quarters = y
b)Total number of coins is 33.
So the first equation
x + y = 33 .......... (1)
ALso, number of nickels is 5 greater than three times the number of quarters.
This gives us the second equation,
x= 5 + 3y .........(2)
c) Using the method of substitution, substitute the value of x from equation 2 in equation 1
5+ 3y +y =33
5+4y=33
4y= 33-5
4y = 28
y=7
Putting the value of y in equation (2)
x= 5+ 3*7
x= 5+21
x=26
d)Number of quarters (y)= 7
Number of nickels (x) =26
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