Question 1042230: A city commission has proposed two tax bills. The firs bill requires that a homeowner pays $1800 plus 3% of the assessed home value in taxes. The second bill requires taxes of $200 8% of the assessed home value. what price range of the home assessment would make the first bill a better deal for the homeowner?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! First is 1800+0.03x, where x is home value
Second is 200+0.08x
set them equal and solve for x
1800+0.03x=200+0.08x
1600=0.05x
divide by 0.05 (or multiply by 20)
32000=x
That is where they are equal.
One can try 30,000 and compare both
The first would be 1800+0.03(30,000)=2700
The second would be 200+0.08(200)=360
So for house prices > 32,000, plan 1 would be better.
------------------------------
Set it as an inequality.
1800+0.03x<200+0.08x
-0.05x<-1600
divide by -20 and flip inequality signs
x>$32,000
|
|
|
