SOLUTION: I'm not entirely sure where this fits, so I'll put it here. Here's my problem:
Tickets to the premiere of "The Bigger They Are, the Harder They Hit" cost $7 for adults and $4 for
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Tickets to the premiere of "The Bigger They Are, the Harder They Hit" cost $7 for adults and $4 for
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Question 1042228: I'm not entirely sure where this fits, so I'll put it here. Here's my problem:
Tickets to the premiere of "The Bigger They Are, the Harder They Hit" cost $7 for adults and $4 for kids. If 83 people attended the premiere and the theater sold $527 worth of tickets, how many adults attended the premiere? Found 2 solutions by jorel555, Boreal:Answer by jorel555(1290) (Show Source):
You can put this solution on YOUR website! Let n be the number of adult tickets sold. Then:
7n+4(83-n)=527
3n=195
n=65 adult tickets sold. ☺☺☺☺
You can put this solution on YOUR website! adult tickets sold=x
child tickets sold=83-x. One could use x and y, but this way keeps it with one variable
7x+4(83-x)=527
7x+332-4x=527
3x+332=527
3x=195
x=65. If it is not an integer, something is wrong in the problem or the solution.
65 adult tickets@$7=$455 ANSWER
18 child tickets$4=$72
Total is $527.
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