SOLUTION: The area of a square with sides of 2 feet is 4 square feet. The area of a square with sides of 4 feet is 16 square feet. What ordered pairs fit this situation?

Algebra ->  Rectangles -> SOLUTION: The area of a square with sides of 2 feet is 4 square feet. The area of a square with sides of 4 feet is 16 square feet. What ordered pairs fit this situation?      Log On


   



Question 1041979: The area of a square with sides of 2 feet is 4 square feet. The area of a square with sides of 4 feet is 16 square feet. What ordered pairs fit this situation?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
x = side length
y = area

Each ordered pair is of the form (x,y)

"The area of a square with sides of 2 feet is 4 square feet" means we have the ordered pair (x,y) = (2,4) where x = 2 and y = 4.

"The area of a square with sides of 4 feet is 16 square feet" means we have the ordered pair (x,y) = (4,16) where x = 4 and y = 16

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So the two ordered pairs are (2,4) and (4,16)