SOLUTION: Solve for x:{{{(4x+3)/(x-6)+(x-4)/(6-x)=44/(2x-12)}}}

Algebra ->  Expressions -> SOLUTION: Solve for x:{{{(4x+3)/(x-6)+(x-4)/(6-x)=44/(2x-12)}}}      Log On


   



Question 1041844: Solve for x:%284x%2B3%29%2F%28x-6%29%2B%28x-4%29%2F%286-x%29=44%2F%282x-12%29
Found 2 solutions by Edwin McCravy, josmiceli:
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
%284x%2B3%29%2F%28x-6%29%2B%28x-4%29%2F%286-x%29=44%2F%282x-12%29

All the denominators are in descending order except
the denominator 6-x.  So we first get it in descending
order -x+6.  Since it begins with a negative sign we
factor out the negative and that changes the signs
inside the parentheses:
        6-x = -x+6 = -(x-6)

Then we factor the denominator 2x-12 as 2(x-6)

%284x%2B3%29%2F%28x-6%29%2B%28x-4%29%2F%28-%28x-6%29%29=44%2F%282%28x-6%29%29 

We bring the negative sign of denominator -(x-6) in 
front of the fraction.  

Also on the right of the equal sign we can cancel
the 2 into the 44 and get 22:

%284x%2B3%29%2F%28x-6%29-%28x-4%29%2F%28x-6%29=22%2F%28x-6%29  

Now the LCD is just x-6.  So we multiply through
by that and get:

%284x%2B3%29-%28x-4%29=22

4x%2B3-x%2B4=22

3x%2B7=22

3x=15

x=5

Edwin

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
%284x%2B3%29%2F%28x-6%29%2B%28x-4%29%2F%286-x%29=44%2F%282x-12%29
%284x%2B3%29%2F%28x-6%29%2B%28-x%2B4%29%2F%28x-6%29=44%2F%282x-12%29
+%28+4x+%2B+3+-+x+%2B+4+%29+%2F+%28+x+-+6+%29+=+44%2F%28+2x+-+12+%29+
+%28+3x+%2B+7+%29+%2F+%28+x+-+6+%29++=+22+%2F+%28+x+-+6+%29+
Note that +x+ cannot = +6+
( division by zero is not allowed )
Multiply both sides by +x+-+6+
+3x+%2B+7+=+22+
+3x+=+15+
+x+=+5+
-----------------------
check:
%284x%2B3%29%2F%28x-6%29%2B%28x-4%29%2F%286-x%29=44%2F%282x-12%29
%284%2A5%2B3%29%2F%285-6%29%2B%285-4%29%2F%286-5%29=44%2F%282%2A5-12%29
+23+%2F+%28-1%29+%2B+1+%2F+1+=+44+%2F+%28-2%29+
+-23+%2B+1+=+-22+
+-22+=+-22+
OK