SOLUTION: Ashely has dimes, nickels, and quarters. The number of dimes is 3 more than 2 times the number of nickels. The number of quarters is three times the number of dimes. If the coins a

Algebra ->  Average -> SOLUTION: Ashely has dimes, nickels, and quarters. The number of dimes is 3 more than 2 times the number of nickels. The number of quarters is three times the number of dimes. If the coins a      Log On


   



Question 1041832: Ashely has dimes, nickels, and quarters. The number of dimes is 3 more than 2 times the number of nickels. The number of quarters is three times the number of dimes. If the coins are worth a total of $14.80, how many of each kind does she have?
Answer by jorel555(1290) About Me  (Show Source):
You can put this solution on YOUR website!
Let n equal nickels. Then dimes equal 2n+3; and quarters are 3(2n+3), or 6n+9. So:
5n+10(2n+3)+25(6n+9)=1480
175n+255=1480
175n=1225
n=7
2n+3=17
6n+9=51
Ashely has 7 nickels, 17 dimes, and 51 quarters. ☺☺☺☺