SOLUTION: A child is running on a moving sidewalk in an airport. When he runs against the sidewalk's motion, he travels 75 feet in 15 seconds. When he runs with the sidewalk's motion, he tra

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Question 1041826: A child is running on a moving sidewalk in an airport. When he runs against the sidewalk's motion, he travels 75 feet in 15 seconds. When he runs with the sidewalk's motion, he travels 99 feet in 9 seconds. What is the rate of the child on a still sidewalk and what is the rate of the moving sidewalk?
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
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75%2F5 =  5 = u - v,    
99%2F9 = 11 = u + v,

where 75%2F5 is the boy's speed relative to the floor when moving against . . .
99%2F9 is the boy's speed relative to the floor when moving with . . .

u is the boy's speed relative to the moving sidewalk, v is the speed of sidewalk relative to the floor.

S, you have this two basic equations:

u - v =  5,   (1)   and
u + v = 11.   (2)

Add eqns(1) and (2) (both sides). You will get 

2u = 5 + 11 = 16  --->  u = 16%2F2 = 8 ft%2Fs - speed of the boy rel. to the sidewalk.

The v = u - 5 = 8 - 5 = 3 ft%2Fs is the speed of sidewalk rel. to the floor.

Answer.  8 ft%2Fs and 3 ft%2Fs.

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