SOLUTION: Timothy has 1 gallon of 6% bleach, assume 94% is water. Timothy decides to dilute the bleach separately. Timothy pours 10mL, 9mL, 8mL, 7mL, 6mL, and 1mL, of the bleach into 6 d

Let n mL = 10mL, 9mL, 7mL, 6mL or 1mL

In each container, we are pouring in n mL of 6% bleach,
and 10-n mL of water 

         
                milliliters   percent     milliliters
                    of      of bleach      of pure 
                  liquid    as decimal      bleach    
Bleach solution     n          0.06         0.06n 
Water             10-n         0.00         0.00(10-n)
Mixture            10                       0.06n

Then to find the percent of bleach in the mixture we divide
the number of milliliters of bleach solution by the number 
of milliliters of liquid.

                milliliters   percent     milliliters
                    of      of bleach      of pure 
                  liquid    as decimal      bleach    
Bleach solution     n          0.06         0.06n 
Water             10-n         0.00         0.00(10-n)
Mixture            10        0.06n/10       0.06n


percent of bleach as a decimal = 0.06n/10 = .006n

For n = 10 mL, 0.06(10)/10 = .06 = 6% <- (can't pour in any 
                                        water for it's full of 6%)
For n = 9 mL, 0.06(9)/10 = .054 = 5.4%

For n = 8 mL, 0.06(8)/10 = .048 = 4.8%

For n = 7 mL, 0.06(7)/10 = .042 = 4.2%

For n = 6 mL, 0.06(6)/10 = .036 = 3.6%

For n = 1 mL, 0.06(1)/10 = .006 = 0.6%

Edwin