SOLUTION: A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function. What is the maximum height that the ball will reach?
h(t)=76t-16t^2
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-> SOLUTION: A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function. What is the maximum height that the ball will reach?
h(t)=76t-16t^2
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Question 1041381: A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function. What is the maximum height that the ball will reach?
h(t)=76t-16t^2
Do not round your answer Answer by ikleyn(52754) (Show Source):
You can put this solution on YOUR website! .
A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function.
What is the maximum height that the ball will reach?
h(t)=76t-16t^2
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They ask you: what is the maximum of this quadratic function:
h(t) = . (1)
Do you remember how to find the vertex of the parabola y = ?
The maximum is reached at x = .
In your case the maximum height is reached at the time moment t = = = seconds = seconds.
Next, to calculate the maximal height, you need to substitute this value of the time t into the formula for the height (1).
Then you get h(t) = h(19/8) = ft.
You can complete calculations on your own.
