SOLUTION: How do I complete this problem? #1. 6&#8730;7-^3&#8730;x+2&#8730;7-6^3&#8730;x 6 (square root 7) minus (3rd power) (square root x) + 2 (square root 7)

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Question 1041243: How do I complete this problem?
#1. 6√7-^3√x+2√7-6^3√x
6 (square root 7) minus (3rd power) (square root x) + 2 (square root 7) - 6 to the third power (square root x).
Sorry if I confused anyone.
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!

The answer is . Below I show how/why

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Notice how comes up twice. So does . This suggests we'll be combining like terms.

They are somewhat complicated expressions. Let's replace them temporarily.

Let

we'll use those equations above to simplify

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Replace EVERY copy of with P

Replace EVERY copy of with Q

After this point, we combine like terms. Just like how x+3x simplifies to 4

Group like terms

Distributive property

Simplify

Drop unneeded parenthesis

Replace P with

Replace Q with

Side Note: is read as "cube root of x". It's similar, but not identical, to the square root.

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So the final answer is

SOLUTION: How do I complete this problem? #1. 6&#8730;7-^3&#8730;x+2&#8730;7-6^3&#8730;x 6 (square root 7) minus (3rd power) (square root x) + 2 (square root 7) - 6 to the third power

SOLUTION: How do I complete this problem? #1. 6√7-^3√x+2√7-6^3√x 6 (square root 7) minus (3rd power) (square root x) + 2 (square root 7) - 6 to the third power