SOLUTION: Q: two line segment in the x y plane form a right triangle with the x axis,Having vertices (2,a),(0,0),(10,0).what is the area of triangle?

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Question 1041012: Q: two line segment in the x y plane form a right triangle with the x axis,Having vertices (2,a),(0,0),(10,0).what is the area of triangle?
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.
Q: two line segment in the x y plane form a right triangle with the x axis, having vertices (2,a),(0,0),(10,0).
What is the area of triangle?
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It is clear that the vertex (2,a) is the right angle vertex and the segment [(0,0 - (10,0)] is the hypotenuse.

Then you can write the Pythagorean equation in the form

2%5E2+%2B+a%5E2+%2B+%2810-2%29%5E2+%2B+a%5E2 = 10%5E2.       (1)

It is your equation to find the unknown value of "a".

Simplify and solve it:

4+%2B+a%5E2+%2B+64+%2B+a%5E2 = 100,

2a%5E2 = 100+-+64+-+4,

2a%5E2 = 32  --->  a%5E2 = 16  --->  a = 4.

Now, the hypotenuse has the length 10, while the altitude drawn to the hypotenuse has the length 4.

Hence, the area of the triangle is %281%2F2%29%2A10%2A4 = 20 square units.

Answer.  The area of the triangle is 20 square units.


Comment from student: can you tell me how you made this equation.


My response:
Let A be the point (0,0) in the coordinate plane (the origin);
let B be the point (2,a), and let C be the point (10,0).
Then the triangle ABC is right-angled triangle, according to the condition.
with the vertex B as the right angle and the segment AC as the hypotenuse.

Next, draw the perpendicular from the vertex B to the hypotenuse AC. The foot of this perpendicular is the point D = (2,0).

I recommend you to make a sketch of the triangle ABC and draw this perpendicular CD.

Now you have two right angled triangles, ADB and CDB.

From the triangle ADB you have abs%28AB%29%5E2 = 2%5E2+%2B+a%5E2.
From the triangle CDB you have abs%28BC%29%5E2 = %2810-2%29%5E2+%2B+a%5E2.

The equation (1) in my very first post is

abs%28AB%29%5E2 + abs%28BC%29%5E2 = abs%28AC%29%5E2.

Everything is so obvious . . . 

I have a contr-question to you.

Why, when sending your question, you didn't mention the ID number of the problem?