SOLUTION: Help please If an object is propelled upward from a height of s feet at an initial velocity of v feet per​ second, then its height h after t seconds is given by the equa

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Help please If an object is propelled upward from a height of s feet at an initial velocity of v feet per​ second, then its height h after t seconds is given by the equa      Log On


   

Question 1040932: Help please
If an object is propelled upward from a height of s feet at an initial velocity of v feet per​ second, then its height h after t seconds is given by the equation h=-16t^2+vt+s, where h is in feet. If the object is propelled from a height of 8 feet with an initial velocity of 64 feet per​ second, its height h is given by the equation h=-16t^2+64t+8
After how many seconds is the height 36 ​feet?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
h=-16t^2+64t+8
After how many seconds is the height 36 ​feet?
Solve:: -16t^2 + 64t+8 = 36
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-16t^2 + 64t - 26 = 0
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-8t^2 + 32t - 13 = 0
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t = 0.4589 sec
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Cheers,
Stan H.
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