SOLUTION: A ball is thrown into the air with an initial velocity of 64 feet per second from a height of 192 feet. After how many seconds will the ball return to the ground and have a height
Question 1040847: A ball is thrown into the air with an initial velocity of 64 feet per second from a height of 192 feet. After how many seconds will the ball return to the ground and have a height of zero again? Found 2 solutions by ankor@dixie-net.com, ikleyn:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A ball is thrown into the air with an initial velocity of 64 feet per second from a height of 192 feet.
After how many seconds will the ball return to the ground and have a height of zero again?
:
Using the equation:
t = time
-16t^2 force of gravity downward,
64t = initial velocity upward,
192 = initial height
:
-16t^2 + 64t + 192 = 0
simplify, divide equation by -16
t^2 - 4t - 12 = 0
Factors easily to
(t-6)(t+2) = 0
the positive solution
t = 6 sec to return to the ground
:
:
see if that works
-16(6^2) + 64(6) + 192 =
-576 + 384 + 192 = 0
