SOLUTION: The fastest measured pitched baseball left the pitcher's hand at a speed of 45.0 m/s . If the pitcher was in contact with ball over a distance of 1.50 m and produced constant accel
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Question 1040713: The fastest measured pitched baseball left the pitcher's hand at a speed of 45.0 m/s . If the pitcher was in contact with ball over a distance of 1.50 m and produced constant acceleration. (a.) what acceleration did he give the ball, and (b.) how much time did it take him to pitch? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! It starts at zero and accelerates to 45 m/sec --> avg speed = 22.5 m/sec
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t = d/r = 1.5/22.5 = 1/15 second
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Acceleration = 45 m/sec/(1/15 sec) = 675 m/sec/sec
