Question 1040673: Billy-joe purchased a 60 gallon pool for his farm. At 1:00 pm one day Billy-joe placed a hose which filled the pool at a rate of 3 gal/hr. After 10 hours, the horses and cows started drinking the water at a rate of 1 gal/hr. Five hours after that, he noticed the animals and placed a second hose in the pool which filled in at a rate of 2 gal/hr. At what time was the pool finally filled?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! 3*10=30 gallons after 10 hours
minus 1 gal/hr for 5 hours=25 gallons.
If the animals are still drinking, the pool is effectively filling at 1 gal/hr, 2-1, and it will take 35 more hours to fill.
If the animals aren't drinking, the pool will fill at 2 gal/hour and it will be full in 35/2 hours or 17.5 hours.
|
|
|
