Solve for x:
sec^2 x + tanx = 3; 0 < x < 360
------ Substituting 
------ Subtracting 3 from each side
(tan x - 1)(tan x + 2) = 0
tan x - 1 = 0 OR tan x + 2 = 0
tan (x) = 1 is in the 1st and 3rd quadrants, where tan is positive (> 0), so
tan (x) = - 2 is in the 2nd and 4th quadrants, where tan is negative (< 0), so