SOLUTION: I'm having some trouble with this problem and could use your help! Points (–1, 0) and (–9, –8) are endpoints of the diameter of a circle. (a) What is the length of the diameter

Algebra ->  Graphs -> SOLUTION: I'm having some trouble with this problem and could use your help! Points (–1, 0) and (–9, –8) are endpoints of the diameter of a circle. (a) What is the length of the diameter      Log On


   

Question 1040546: I'm having some trouble with this problem and could use your help!
Points (–1, 0) and (–9, –8) are endpoints of the diameter of a circle.
(a) What is the length of the diameter?
(b) What is the center point C of the circle?
(c) Given the point C you found in part (b), state the point symmetric to C about the x-axis.
am I using the distance formula: sqrt((x2-x1)^2 + (y2-y1)^2)
any help or guidance on this would be amazing, thank you!
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
Question part (c) does not mean anything. Do you want the equation of the circle instead?

(a):
Distance Formula;
sqrt%28%28-1-%28-9%29%29%5E2%2B%280-%28-8%29%29%5E2%29

(b):
Midpoint Formula;
If midpoint is the ordered pair, (h,k), then h=%28-1-9%29%2F2 and k=%280-8%29%2F2.



(c)
Finish those computations. The distance will give you the DIAMETER, which is twice the radius. The midpoint in (b) is the center, indicated as (h,k). If using r as the radius, and if you want the equation for the circle, the standard form would be of a format %28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2.