SOLUTION: A bowl of soup at 180° F. is placed in a room of constant temperature of 70° F. The temperature T of the soup t minutes after it is placed in the room is given by
T(t
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T(t
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Question 1040496: A bowl of soup at 180° F. is placed in a room of constant temperature of 70° F. The temperature T of the soup t minutes after it is placed in the room is given by
T(t) = 70 + 110 e^ – 0.075 t
Find the temperature of the soup 32 minutes after it is placed in the room. (Round to the nearest degree.) Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! Just substitute t = 32 into the equation:
F, or 80 degrees Fahrenheit.
BTW, this is an example of Newton's law of cooling.
