You can put this solution on YOUR website! Assume you mean + 1 =
Multiply equation by (u-2)(u-3), cancel the denominators and you have
(u-3)(u+7) + (u-2)(u-3) = (u-2)(u+5)
FOIL
u^2 + 7u - 3u - 21 + u^2 - 3u - 2u + 6 = u^2 + 5u -2u - 10
Combine like terms
u^2 + 4u - 21 + u^2 - 5u + 6 = u^2 + 3u - 10
Combine again on the left
u^2 + u^2 - u^2 + 4u - 5u - 3u - 21 + 6 + 10 = 0
u^2 - 4u - 5u = 0
Factors to
(u-5)(u+1) = 0
two solutions
u = 5
u = -1
:
You should check both solutions in the original equation