SOLUTION: 1. Solve for x. x^(2)10^(x) − 6x10^(x) = 2710^(x) 2. Exponential equation in terms of logs. t=? 10(1.375)^19t = 50? 3. e^x = -9x find solutions for x

Algebra ->  Equations -> SOLUTION: 1. Solve for x. x^(2)10^(x) − 6x10^(x) = 2710^(x) 2. Exponential equation in terms of logs. t=? 10(1.375)^19t = 50? 3. e^x = -9x find solutions for x      Log On


   



Question 1040420: 1. Solve for x. x^(2)10^(x) − 6x10^(x) = 2710^(x)
2. Exponential equation in terms of logs. t=? 10(1.375)^19t = 50?
3. e^x = -9x find solutions for x

Answer by ikleyn(52903) About Me  (Show Source):
You can put this solution on YOUR website!
.
1. Solve for x. x^(2)10^(x) − 6x10^(x) = 2710^(x)
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x%5E2%2A10%5Ex+-+6x%2A10%5Ex = 27%2A10%5Ex     (notice I made changes in the right side !)

Cancel 10%5Ex in both sides. You will get

x%5E2+-6x = 27,   or

x%5E2+-6x+-+27 = 0.

Factor:

(x+3)*(x-9) = 0.

The roots are x = -3 and x = 9.

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