SOLUTION: two cars pas each other traveling in opposite directions on a highway, one is goig 1.5 times as fast as the other. at the end of 3.5 hours they are 192.5 miles apart. find each car
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Question 104042: two cars pas each other traveling in opposite directions on a highway, one is goig 1.5 times as fast as the other. at the end of 3.5 hours they are 192.5 miles apart. find each cars rate.
You can put this solution on YOUR website! Two cars pass each other traveling in opposite directions on a highway, one is going 1.5 times as fast as the other. At the end of 3.5 hours, they are 192.5 miles apart. Find each cars rate.
:
Let s = speed of the slower car
Then
(1.5s) = speed of the faster car
:
Write a distance equation: Distance = time * speed.
:
They both will be traveling for 3.5 hr
;
Fast car dist + slow car dist = 192.5
3.5(1.5s) + 3.5s = 192.5
5.25s + 3.5s = 192.5
8.75s = 192.5
s = 192.5/8.75
s = 22 mph is the slow car
Then
1.5(22)) = 33 mph is the fast car
:
:
Check solution:
3.5(33) + 3.5(22) =
115.5 + 77 = 192.5: confirms out solution
