SOLUTION: Find the 95% confidence interval for the standard deviation of the lengths of pipes if a sample of 11 pipes has a standard deviation of 12 inches. A. 70.3 < < 443.5 B. 13.0

Algebra ->  Probability-and-statistics -> SOLUTION: Find the 95% confidence interval for the standard deviation of the lengths of pipes if a sample of 11 pipes has a standard deviation of 12 inches. A. 70.3 < < 443.5 B. 13.0      Log On


   



Question 1040410: Find the 95% confidence interval for the standard deviation of the lengths of pipes if a sample of 11 pipes has a standard deviation of 12 inches.
A.
70.3 < < 443.5
B.
13.0 << 11.0
C.
8.4 << 21.1
D.
133.0 << 155.0

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Let's set up some notation.

XL = left chi-square critical value
XR = right chi-square critical value

The X will stand for the greek letter chi (pronounced "kai", rhymes with "sky"). R for "right" and L for "left.

XL and XR are the chi-square critical values such that P(XL < chi-square < XR) = 0.95
basically the area between XL and XR is 0.95

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Use a chi-square table of values. Highlight the df = 10 row (n = 11, so df = n-1 = 11-1 = 10).
This row is marked in red.

Keep in mind that if the confidence level is 95%, then alpha = 1-CL = 1-0.95 = 0.05. Cut this in half to get 0.05/2 = 0.025

Mark the column that has 0.025 at the top. I marked in blue. The blue and red boxes intersect at the value 20.483. Let's call this XR, so XR = 20.483 approximately

Then we compute 1 - 0.025 = 0.975

Mark the column that has 0.975 at the top. This is marked in green. The green and red boxes intersect at 3.247



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So we just found that
XL = 3.247
XR = 20.483
both are approximate. These are the chi-square critical values.

we will plug in
n = 11 (sample size)
s = 12 (standard deviation

Use the values to compute the confidence interval















where is the greek letter sigma and it is the population standard deviation


So the answer is choice C