Question 1040299: 1. Please help me to solve this? (2a - 3b) ( a + 12b)
2. Please help me to solve this? (-m + 6n ) ( -3m - 7n)
3. Please help me to solve this? (-4p - q) ( 2p + 9q)
4. Please help me to solve this? -3(h - 11) (5h - 5)
5. Please help me to solve this [( x + 3) + 2 ] [( x + 3) - 5]
Thank you in advance
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! multiply each term in the first by each term in the second. There are four terms.
For the first, it would be 2a*2+2a(12b)-3b(a)-3b(12b)=2a^2-3ab+24ab-36b^2
That is 2a^2+21ab-36b^2. Remember, ab and ba are the same.
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The second is 3m^2-11mn-42n^2.
(-m+6n)(-3m-7n)=(-m)(-3m)+(-m)(-7n)+(6n)(-3m)+(6n)(-7n)=3m^2+7mn-18mn-42n^2. There are four terms from a 2 x 2 binomial. Each term in the first is multiplied by each term in the second. There will be a m^2 and n^2 and two mn terms. The others are done the same way.
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The third is -8p^2-38pq-9q^2
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The fourth is done by putting the -3 in last. (5h^2-60h+55), so it becomes -15h^2+180h-165
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The fifth is (x+5)(x-2), because the parentheses don't change anything when there is addition. We can add in any order we choose.
That is foiled out to x^2+3x-10.
The long way is (x+3)^2-5(x+3)+2(x=3)-10
That is (x+3)^2-3(x+3)-10
That is x^2+6x+9-3x-9-10
That is x^2+3x-10
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