SOLUTION: y=k(x-4)(x+2) The graph of the quadratic equation above, where k is a constant, has a vertex at point (a,b) in the xy-plane. Which of the following is equal to a?

Algebra ->  Graphs -> SOLUTION: y=k(x-4)(x+2) The graph of the quadratic equation above, where k is a constant, has a vertex at point (a,b) in the xy-plane. Which of the following is equal to a?      Log On


   

Question 1040252: y=k(x-4)(x+2)
The graph of the quadratic equation above, where k is a constant, has a vertex at point (a,b) in the xy-plane. Which of the following is equal to a?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Vertex is between the zeros, being at x=%284-2%29%2F2=highlight%281=a%29.

The actual value for coordinate b would be unknown because the factor k is unknown.