Question 1040250: If 90 people attend a concert and tickets for adults cost $2.25 while tickets for children cost $1.5 and total receipts for the concert was $163.5, how many of each went to the concert?
Ngoc invests a total of $22,000 in two accounts paying 8% and 11% annual interest, respectively. How much was invested in each account if, after one year, the total interest was $1,835.00.
$ was invested at 8% and
$ was invested at 11%.
Jolene invests her savings in two bank accounts, one paying 4 percent and the other paying 10 percent simple interest per year. She puts twice as much in the lower-yielding account because it is less risky. Her annual interest is 7164 dollars. How much did she invest at each rate?
Amount invested at 4 percent interest is $
Amount invested at 10 percent interest is $
If 78 people attend a concert and tickets for adults cost $3.75 while tickets for children cost $3 and total receipts for the concert was $267, how many of each went to the concert?
adults
children
If 90 people attend a concert and tickets for adults cost $2.25 while tickets for children cost $1.5 and total receipts for the concert was $163.5, how many of each went to the concert?
adults
children
Alan invests $10700 in two different accounts. The first account paid 10 %, the second account paid 6 % in interest. At the end of the first year he had earned $858 in interest. How much was in each account?
$ at 10 %
$ at 6 %
Scott invests $9100 in two different accounts. The first account paid 12 %, the second account paid 10 % in interest. At the end of the first year he had earned $1028 in interest. How much was in each account?
$ at 12 %
$ at 10 %
Guadalupe invests $1100 in one account and $2500 in an account paying 1 % higher interest. At the end of one year she had earned $277 in interest. At what rates did she invest?
$1100 invested at %
$2500 invested at %
Your help i greatly appreciated.
Thank you
Found 2 solutions by addingup, ikleyn:
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! a+c = 90 subtract c from both sides:
a = 90-c
:
2.25a+1.50c = 163.50 substitute for a:
2.25(90-c)+1.50c = 163.50
202.5-2.25c+1.50c = 163.50
-0.75c = -39
c = 52 were children, and 90-52 = 38 were adults
-o-o-o-o-o-o-o-o-o-o-o-o-o-o-o-o-o-o-o-o-o-o
:
0.08x+0.11(22,000-x) = 1,835
0.08x+2,420-0.11x = 1,835
-0.03x = -585
x = 19,500 is invested at 8% and 22,000-19,500 = 2,500 is invested at 11%
-o-o-o-o-o-o-o-o-o-o-o-o-o-o-o-o-o-o-o-o-o-o
:
0.04(2x)+0.10x = 7,164
0.08x+0.10x = 7,164
0.18x = 7,164
x = 39,800 is invested at 4% and this is 2 times as much as she has invested at 10%: 39,800/2 = 19,900 is invested at 10%
Answer by ikleyn(52787)  (Show Source):
You can put this solution on YOUR website! .
When you post a series of problems like this, you demonstrate that you know nothing, don't want to learn and don't want to work yourself.
Doing this way, you make very bad impression about yourself.
Or, may be, you are an industrialist to exploit volunteers? (We are volunteers).
Then please be aware that in this site we do not serve industrialists who work to fill their own web-sites in this way.
The rule of this site is one question/one problem per post.
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