SOLUTION: Jane is saving money to buy a laptop computer costing $1200. Jane models her savings by the equation, y=360+120x, where x is the number of consecutive monthly deposits and y is the

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Jane is saving money to buy a laptop computer costing $1200. Jane models her savings by the equation, y=360+120x, where x is the number of consecutive monthly deposits and y is the      Log On


   

Question 1040238: Jane is saving money to buy a laptop computer costing $1200. Jane models her savings by the equation, y=360+120x, where x is the number of consecutive monthly deposits and y is the balance in the account. If Jane makes her first deposit in January 2010 and continues making deposits each month thereafter, in what month and year will she be able to buy her laptop?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
You want to know when the balance in her account
reaches $1200, so
+1200+=+360+%2B+120x+
+120x+=+840+
+x+=+7+
There are 7 consecutive monthly deposits
She can buy laptop 6 months after the 1st deposit
in Jan 2010.
That is July 2010