Question 1040195: 1. What must be the value of k so that 5k-3, k+2, and 3k-11 will form an arithmetic sequence?
2. which term of the arithmetic sequence whose first term is -3,common difference is 2, and last term is 23?
3. find a sub 1 if a sub 8=54 and a sub 9=60.
4. find the 9th term of the arithmetic sequence with asub1 =10 and d= -1/2
5. give the arithmetic sequence of 5 terms if the first term is 8 and the last term is 100.
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52803)   (Show Source):
You can put this solution on YOUR website! .
1. What must be the value of k so that 5k-3, k+2, and 3k-11 will form an arithmetic sequence?
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if 5k-3, k+2, and 3k-11 will form an arithmetic sequence, then
the differece (3-rd - 2-nd) = (2-nd - 1-st), or
(3k-11) - (k+2) = (k+2) - (5k-3).
To find the value of "k", simplify and solve this equation:
3k - 11 - k - 2 = k+2 - 5k +3, --->
2k - 13 = -4k +5, --->
2k + 6k = 5 + 13,
6k = 18 ---> k =  = 3.
One question per post please.
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website! 1. What must be the value of k so that 5k-3, k+2, and 3k-11 will form an arithmetic sequence?
2. which term of the arithmetic sequence whose first term is -3,common difference is 2, and last term is 23?
3. find a sub 1 if a sub 8=54 and a sub 9=60.
4. find the 9th term of the arithmetic sequence with asub1 =10 and d= -1/2
5. give the arithmetic sequence of 5 terms if the first term is 8 and the last term is 100.
Why would you want to DUMP all your work on others? Don't you think you need to attempt MOST of them?
 . Try to determine how that value was arrived at, and then try figuring out the rest.
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