SOLUTION: One end of a diameter of a circle with equation x^2+y^2-4x+4y=2 is (3,1).
Find the coordinates of the other end of the diameter.
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-> SOLUTION: One end of a diameter of a circle with equation x^2+y^2-4x+4y=2 is (3,1).
Find the coordinates of the other end of the diameter.
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Question 1040186: One end of a diameter of a circle with equation x^2+y^2-4x+4y=2 is (3,1).
Find the coordinates of the other end of the diameter. Answer by Edwin McCravy(20065) (Show Source):
