SOLUTION: log12(x+1)+log12^x=1
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Question 1040047
:
log12(x+1)+log12^x=1
Answer by
ankor@dixie-net.com(22740)
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Assuming you mean
combine
The exponent equiv
x^2 + x = 12
A quadratic equation
x^2 + x - 12 = 0
Factors to
(x+4)(x-3) =
x = 3, only the positive solution will work here