SOLUTION: 1. A 25 N object requires a 5.0 N to start moving over a horizontal surface. What is the coefficient of static friction? 2.A 12 N cart is moving on a horizontal surface with a

Algebra ->  Vectors -> SOLUTION: 1. A 25 N object requires a 5.0 N to start moving over a horizontal surface. What is the coefficient of static friction? 2.A 12 N cart is moving on a horizontal surface with a      Log On


   

Question 1040014: 1. A 25 N object requires a 5.0 N to start moving over a horizontal surface. What is the coefficient of static friction?

2.A 12 N cart is moving on a horizontal surface with a coefficient of kinetic friction of 0.20. What force of friction must be overcome to keep the object moving at a constant velocity?

Found 2 solutions by solver91311, ikleyn:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Physics problem; Algebra website. Sort of like trying to buy a pound of 10d nails at the grocery store.

John

My calculator said it, I believe it, that settles it

Answer by ikleyn(53938) About Me  (Show Source):
You can put this solution on YOUR website!
.
1. A 25 N object requires a 5.0 N to start moving over a horizontal surface. What is the coefficient of static friction? 

k%5Bfriction%5D = F%5Bshift%5D%2FF%5Bnormal%5D

Coefficient of friction is the ratio of the magnitude (modulus) of the shifting force F%5Bshift%5D applied to the body 
and directed along the surface to the magnitude (modulus) of the normal force F%5Bn%5D directed normal to the surface (see this Wikipedia article).


I  our case, k%5Bfriction%5D = 5%2F25 = 0.2.

2. A 12 N cart is moving on a horizontal surface with a coefficient of kinetic friction of 0.20. What force of friction
must be overcome to keep the object moving at a constant velocity? 

F%5Bfriction%5D = k%5Bfriction%5D%2AF%5Bn%5D = 0.2*12 = 2.4 N.

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