SOLUTION: A person had a collection of 20 cent, 10 cent and 5 cent coins in the ratio 3:4:5. The value of the 20 cent coins was $2.80 more than the value of the 5 cent coins. What was the nu

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: A person had a collection of 20 cent, 10 cent and 5 cent coins in the ratio 3:4:5. The value of the 20 cent coins was $2.80 more than the value of the 5 cent coins. What was the nu      Log On


   

Question 1039951: A person had a collection of 20 cent, 10 cent and 5 cent coins in the ratio 3:4:5. The value of the 20 cent coins was $2.80 more than the value of the 5 cent coins. What was the number of 10 cent coins he had?
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
Start with the 20 cent coins and 5 cent coins. Call their counts, x and z.

Use their VALUES description.
20x=2.80%2B5z

Look at their ratio from the other given information.
3%2F5=x%2Fz

You should be able to solve for both x and z. Can you continue solving the problem from that?