SOLUTION: Two painters paint a house in 3 days. The first painter can finish the house in 4 days if he works alone. If the second painter works alone how many days will he need to finish the

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Two painters paint a house in 3 days. The first painter can finish the house in 4 days if he works alone. If the second painter works alone how many days will he need to finish the      Log On


   



Question 1039878: Two painters paint a house in 3 days. The first painter can finish the house in 4 days if he works alone. If the second painter works alone how many days will he need to finish the house on his own?
Found 2 solutions by josmiceli, ikleyn:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Add their rates of working to get their
rate working together
1st painter's rate:
( 1 house painted ) / ( 4 days )
Let +1%2Ft+ = the 2nd painter's rate of painting
which is ( 1 house painted ) / ( t days )
---------------------------------
+1%2F4+%2B+1%2Ft+=+1%2F3+
Multiply both sides by +12t+
+3t+%2B+12+=+4t+
+t+=+12+
------------
The 2nd painter, working alone, finishes the house in 12 days

Answer by ikleyn(52879) About Me  (Show Source):
You can put this solution on YOUR website!
.
For the bunch of lessons on joint-work and rate-of-work see the lessons
    - Using Fractions to solve word problems on joint work,
    - Solving more complicated word problems on joint work,
    - Selected joint-work word problems from the archive
in this site.

Read them, and you will learn how to solve such problems once and for all.

Read them and get be trained in solving joint-work problems.

It is the best thing to read on the summer time.