SOLUTION: The sum of three consecutive even integers is -240. What are the integers?

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Question 103954: The sum of three consecutive even integers is -240. What are the integers?
Found 2 solutions by jim_thompson5910, doukungfoo:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Consecutive even integers follow the form: 2x, 2x%2B2, 2x%2B4, ...., etc.

So the sum of sum of three consecutive even integers is

%282x%29%2B%282x%2B2%29%2B%282x%2B4%29=-240



6x%2B6=-240 Combine like terms on the left side


6x=-240-6Subtract 6 from both sides


6x=-246 Combine like terms on the right side


x=%28-246%29%2F%286%29 Divide both sides by 6 to isolate x



x=-41 Divide

--------------------------------------------------------------
Answer:
So our answer is x=-41


So now plug in x=-41 into 2x, 2x%2B2 and 2x%2B4 to find the numbers

1st number: 2%28-41%29=-82.... So our first number is -82

2nd number: 2%28-41%29%2B2=-80.... So our second number is -80

3rd number: 2%28-41%29%2B4=-78.... So our third number is -78


So our three numbers are: -82,-80, and -78

Check:
-82-80-78=-240
-240=-240 works

Answer by doukungfoo(195) About Me  (Show Source):
You can put this solution on YOUR website!
Ok we need to find three consecutive intergers.
Lets call the smallest interger x
So if the other two intergers are consecutive then
the second integer equals x+1
and the last interger equals x+2
Given: the sum of three consecutive intergers is -240
Now write and equation to express this and solve for x:
(x)+(x+1)+(x+2) = -240
x+x+1+x+2 = -240
3x + 3 = -240
3x = -243
x = -81
use this to find the other intergers
second interger = x+1
second interger = -81+1
second interger = -80
----------------------
third interger = x+2
third interger = -81+2
third interger = -79
Answer: the intergers are -81, -80, -79
Check answers:
The three intergers should add up to -240
(-81)+(-80)+(-79) = -240
-240 = -240