SOLUTION: f(x)=4x^2=3x-1

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Question 1039416: f(x)=4x^2=3x-1
Found 3 solutions by chen.aavaz, Alan3354, MathTherapy:
Answer by chen.aavaz(62) About Me  (Show Source):
You can put this solution on YOUR website!
This is a quadratic equation:
4%2Ax%5E2-3%2Ax%2B1=0
which has no solution / roots in real numbers, because the discriminant
3%5E2-4%2A4%2A1 is negative.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
4x^2=3x-1
4x^2-3x+1 = 0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 4x%5E2%2B-3x%2B1+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-3%29%5E2-4%2A4%2A1=-7.

The discriminant -7 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -7 is + or - sqrt%28+7%29+=+2.64575131106459.

The solution is , or
Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+4%2Ax%5E2%2B-3%2Ax%2B1+%29

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

f(x)=4x^2=3x-1
Too many equals signs.

Aren't you supposed to ask a question if you submit a math problem?