SOLUTION: Write the equation in standard form of the circle whose center is (3,-5) and passes through point (7,1)

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Question 1039381: Write the equation in standard form of the circle whose center is (3,-5) and passes through point (7,1)
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Radius is the distance from center (3,-5) to the point on the circle, (7,1).

%28x-3%29%5E2%2B%28x%2B5%29%5E2=%283-7%29%5E2%2B%28-5-1%29%5E2

Just needs to be simplified.

Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.
Write the equation in standard form of the circle whose center is (3,-5) and passes through point (7,1)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The equation of the circle is

%28x-3%29%5E2+%2B+%28y-%28-5%29%29%5E2 = r%5E2,

where "r" is the radius, or

%28x-3%29%5E2+%2B+%28y%2B5%29%5E2 = r%5E2.

"r" is the distance from the center to the given point in the circle, which is

r%5E2 = %287-3%29%5E2+%2B+%281+-+%28-5%29%29%5E2 = 4%5E2+%2B+6%5E2 = 16 + 36 = 52.

Finally, the equation of the circle is

%28x-3%29%5E2+%2B+%28y%2B5%29%5E2 = 52.