SOLUTION: Write the standard equation of the parabola with its vertex at (3,2) and its focus at (3,0) A) -8(y-2)=(x-3)^2 B) 8(y-2)=(x-3)^2 C)12(x-3)=(y-2)^2 D) -12(x-3)=(y-2)^2

Algebra ->  Rectangles -> SOLUTION: Write the standard equation of the parabola with its vertex at (3,2) and its focus at (3,0) A) -8(y-2)=(x-3)^2 B) 8(y-2)=(x-3)^2 C)12(x-3)=(y-2)^2 D) -12(x-3)=(y-2)^2      Log On


   

Question 1039376: Write the standard equation of the parabola with its vertex at (3,2) and its focus at (3,0)
A) -8(y-2)=(x-3)^2
B) 8(y-2)=(x-3)^2
C)12(x-3)=(y-2)^2
D) -12(x-3)=(y-2)^2
Answer by FrankM(1040) About Me  (Show Source):
You can put this solution on YOUR website!
it starts with y-k=a(x-h)^2
so entering the vertex, we have
y-2=a(x-3)^2
this reduces the choices to A or B.
With a vertex at (3,2) and its focus below it, at (3,0), the parabola opens downward, and the 'a' value must be negative. Choice A is the only possible solution.