Question 1039200: Find the general equation of a line passing through (0,k) and (k,k^2) given that k is not equal to 0
So you find the gradient, which is k-1, then what do you do?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! Slope is k^2-k/k=k-1.
Use point slope formula on both points
y-k^2=(k-1)(x-k)
y-k^2=kx-k^2-x+k
y=kx+k-x, or x(k-1)+k
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use other point
y-k-(k-1)x
y=(k-1)x +k
This is the general equation,
if k=4, y=3x+4, and it would pass through (0,4) and (4,16)
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