SOLUTION: Solve for all values in the given intervals:
a) sin^2(x) + sin(x) - 2 = 0 for xER
b) cot(x)cos(x) = cos(x) for xER
Algebra ->
Trigonometry-basics
-> SOLUTION: Solve for all values in the given intervals:
a) sin^2(x) + sin(x) - 2 = 0 for xER
b) cot(x)cos(x) = cos(x) for xER
Log On
Question 1039189: Solve for all values in the given intervals:
a) sin^2(x) + sin(x) - 2 = 0 for xER
b) cot(x)cos(x) = cos(x) for xER Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! factor it
(sin^2x +2)(sin^2x -1)=0
The first gives complex roots; the second factors into (sin x+1)(sin x -1)=0.
Sin x=1, -1
over 0 and 2 pi, this would be pi/2 and 3pi/2.
=========================
cot(x)cos(x) = cos(x)
[cos x/sin x]=1
This occurs at pi/4 and 5 pi/4
