SOLUTION: Please help me solve this equation using base-10 logarithms. 7^(x+4)=4^4^x

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Question 1039175: Please help me solve this equation using base-10 logarithms.
7^(x+4)=4^4^x
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
7^(x+4)=4^4^x
7^(x+4)=256^x
(x+4)*log(7) = x*log(256)
x*log(7) + 4log(7) = x*log(256)
x*(log(256) - log(7)) = log(2401) ---- 7^4 = 2401
x = log(2401)/log(256/7)
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You can use any base for the logs.