SOLUTION: Write an equation of the line that passes through the point P
and is perpendicular to the line with the given equation:
P(1,4); y = -2x + 4
and
Write an equation of the line th
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-> SOLUTION: Write an equation of the line that passes through the point P
and is perpendicular to the line with the given equation:
P(1,4); y = -2x + 4
and
Write an equation of the line th
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Question 1039108: Write an equation of the line that passes through the point P
and is perpendicular to the line with the given equation:
P(1,4); y = -2x + 4
and
Write an equation of the line that passes through the point P
and is perpendicular to the line with the given equation:
P(5,3); y = 5x + 2 Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! P(1,4); y = -2x + 4
The slope is -2, because it is in slope-intercept form.
Perpendicular lines have negative reciprocal slope, or +1/2. The product of -2 and (1/2) is -1
point slope formula (way 1)
y-y1=m(x-x1)
y-4=(1/2)(x-1)
y-4=(1/2)x-(1/2)
y=(1/2)x+(7/2)
y=5x+2 (5,3)
Second has slope of 5 and negative reciprocal is -1/5
way 2
y=mx+b
substitute x,y from point
3=(-1/5)*5+b
3=-1+b
b=4
y=(1/5)x+4
y-3=(-1/5)(x-5)
y=(-1/5)x+4
