Question 1039090: solve
sinxtanx-1=tanx-sinx
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! sinxtanx-1=tanx-sinx
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Multiply thru by cos
sin^2(x) - cos(x) = sin(x) - sin*cos
sin^2 - sin - cos + sin*cos = 0
sin*(sin - 1) + cos*(sin - 1) = 0
(sin + cos)*(sin - 1) = 0
sin = 1
x = pi/2 + n*2pi, n = any integer
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sin = -cos
x = 3pi/4 + n*pi, n = any integer
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