SOLUTION: Solve the following system of linear eqnations. x + y – 3z + 2w = 0 2x - y + 2z – 3w = 0 3x – 2y + z – 4w = 0 - 4x + y – 3z + w = 0

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Solve the following system of linear eqnations. x + y – 3z + 2w = 0 2x - y + 2z – 3w = 0 3x – 2y + z – 4w = 0 - 4x + y – 3z + w = 0      Log On


   

Question 1039067: Solve the following system of linear eqnations.
x + y – 3z + 2w = 0
2x - y + 2z – 3w = 0
3x – 2y + z – 4w = 0
- 4x + y – 3z + w = 0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Use Cramer's rule,

abs%28A%29=-35
,
,
,

abs%28A%5Bw%5D%29=0
,
,
,

abs%28A%5Bx%5D%29=0
,
,
,

abs%28A%5By%5D%29=0
,
,
,

abs%28A%5Bz%5D%29=0
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,
,
So then,
w=abs%28A%5Bw%5D%29%2Fabs%28A%29=0%2F35=0
x=abs%28A%5Bx%5D%29%2Fabs%28A%29=0%2F35=0
y=abs%28A%5By%5D%29%2Fabs%28A%29=0%2F35=0
z=abs%28A%5Bz%5D%29%2Fabs%28A%29=0%2F35=0
.
.
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The only other solution is where the system is dependent, where one row is a multiple of other rows.