SOLUTION: Could you help me with the equation {{{ (-27)^(2/3) }}}

Algebra ->  Exponents -> SOLUTION: Could you help me with the equation {{{ (-27)^(2/3) }}}      Log On


   



Question 103881: Could you help me with the equation
+%28-27%29%5E%282%2F3%29+

Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
-27^(2/3)
cubert-27^2
cubert729
cubert(3*3*3*3*3*3)
cubert(9*9*9)=9 answer.